/bin/sh: -c: line 0: unexpected EOF while looking for matching ``' /bin/sh: -c: line 1: syntax error: unexpected end of file 奇怪的是从提示符执行的时候它是完美的
整个脚本
#!/bin/sh NOW=$(date +"%b-%d-%y") bu_PATH="/home/webserver/" curtime=$(date) echo "" echo "Starting backup: $curtime" echo "" echo "Moving to $bu_PATH" cd $bu_PATH BACKUP_FILE="backup_$NOW.tgz" echo "" echo "The backup file will be called $BACKUP_FILE" RUN_BACKUP="/usr/local/psa/bin/pleskbackup --server --output-file=$bu_PATH$BACKUP_FILE" echo "Running backup...." echo `$RUN_BACKUP` curtime=$(date) echo "Backup complete: $curtime" echo "" echo "Remove older than 7 days of files..." ssh server '/shares/backup/webserver/cleanup.sh' curtime=$(date) echo "" echo "Connecting to FTP: $curtime" sftp -b server <<EOF cd /shares/backup/webserver/ put $bu_PATH$BACKUP_FILE quit EOF; curtime=$(date) echo "FTP Transfer Complete: $curtime" echo "" echo "Cleaning up Local backups" sh /home/cleanup.sh echo "" echo "Clean up log files" find /home/webserver/logs/*.log -mtime +7 -exec rm {} \; echo "Job Complete"
这是crontab项
/home/backup.sh > /home/webserver/logs/BackupLog-`date +%m%d%y`.log
感谢Rob
如果在crontab中使用反引号（`），则需要转义crontab条目中的％符号。
喜欢这个：
/home/backup.sh > /home/webserver/logs/BackupLog-`date +\%m\%d\%y`.log
如果你不逃避他们，他们被视为新行。
你的EOF看起来不对，EOF; 不符合您预期的EOF（删除分号）。
[hlinden @ dolphin tmp] $ cat dog.sh ＃！/斌/庆典 猫<< EOF 狗 猫 EOF; [hlinden @ dolphin tmp] $ sh dog.sh dog.sh：第6行：警告：这里是第3行的文件（由'EOF'结尾） 狗 猫 EOF; [hlinden @ dolphin tmp] $ sed -is / \; // dog.sh [hlinden @ dolphin tmp] $ sh dog.sh 狗 猫 [hlinden @ dolphin tmp] $