使用下面的命令输出，
% curl -v stackoverflow.com/questions * About to connect() to stackoverflow.com port 80 (#0) * Trying 198.252.206.16... * Connected to stackoverflow.com (198.252.206.16) port 80 (#0) > GET /questions HTTP/1.1 > User-Agent: curl/7.29.0 > Host: stackoverflow.com > Accept: */* 我可以做curl -X GET -H "User-Agent: curl/7.29.0" -H "Host: stackoverflow.com" -H "Accept: */*" 198.252.206.16复制请求，但我该如何指定GET /questions在我的命令？
stackoverflow.com/questions
= GET /问题
stackoverflow.com/87whjjgaas.asd
= GET /87whjjgaas.asd
23.123.123.123/questions
= GET /问题
对于
curl -X GET -H“User-Agent：curl / 7.29.0”-H“Host：stackoverflow.com”-H“Accept： / ”198.252.206.16
答案是
curl -X GET -H“User-Agent：curl / 7.29.0”-H“Host：stackoverflow.com”-H“Accept： / ”198.252.206.16/questions
🙂