我越来越疯狂configurationPOSTFIX + DOVECOT +validationSMTP（SASL现在）。 stream行/ imap帐户运作良好，以获得邮箱，但我不能login到smtp使用sasl：
这里：
[root@mail postfix]# telnet localhost smtp Trying ::1... telnet: connect to address ::1: Connection refused Trying 127.0.0.1... Connected to localhost. Escape character is '^]'. 220 localhost ESMTP ehlo localhost 250-localhost 250-PIPELINING 250-SIZE 10240000 250-VRFY 250-ETRN 250-AUTH PLAIN LOGIN CRAM-MD5 250-AUTH=PLAIN LOGIN CRAM-MD5 250-ENHANCEDSTATUSCODES 250-8BITMIME 250 DSN auth plain aW5mby5jb20AaW5mby5jb20AcG9yY29kZGlv 535 5.7.8 Error: authentication failed: base64摘要使用以下（域和通过不同的过程）：
perl -MMIME::Base64 -e 'print encode_base64("[email protected]\[email protected]\0mypass")'
Main.cf：
smtpd_banner = $myhostname ESMTP biff = no append_dot_mydomain = no myhostname = localhost alias_maps = hash:/etc/aliases alias_database = hash:/etc/aliases myorigin = $myhostname mynetworks = 127.0.0.0/8, 151.236.7.0/24 mailbox_size_limit = 0 home_mailbox = Maildir/ virtual_mailbox_domains = /etc/postfix/vhosts virtual_mailbox_base = /home/vmail virtual_mailbox_maps = hash:/etc/postfix/vmaps virtual_minimum_uid = 1000 virtual_uid_maps = static:5000 virtual_gid_maps = static:5000 recipient_delimiter = + inet_interfaces = all smtpd_sasl_auth_enable = yes broken_sasl_auth_clients = yes smtpd_sasl_type = dovecot smtpd_sasl_path = private/auth smtpd_sasl_security_options = noanonymous smtpd_recipient_restrictions = permit_mynetworks,permit_sasl_authenticated,reject_unauth_destination
Dovecot.conf：
auth_mechanisms = plain login cram-md5 auth_verbose = yes auth_debug = yes base_dir = /var/run/dovecot/ info_log_path = /var/log/dovecot.info log_path = /var/log/dovecot log_timestamp = "%Y-%m-%d %H:%M:%S " mail_location = maildir:/home/vmail/%d/%n passdb { args = /etc/dovecot/passwd driver = passwd-file } protocols = imap pop3 service auth { executable = /usr/libexec/dovecot/auth user = root } service imap-login { chroot = login executable = /usr/libexec/dovecot/imap-login user = dovecot } service imap { executable = /usr/libexec/dovecot/imap } service pop3-login { chroot = login executable = /usr/libexec/dovecot/pop3-login user = dovecot } service pop3 { executable = /usr/libexec/dovecot/pop3 } ssl = no userdb { args = /etc/dovecot/users driver = passwd-file } valid_chroot_dirs = /var/spool/vmail protocol pop3 { pop3_uidl_format = %08Xu%08Xv } service auth { unix_listener /var/spool/postfix/private/auth { mode = 0600 user = postfix group = postfix } }
系统信息：
CentOS release 6.5 (Final) postfix-2.6.6-2.2.el6_1.x86_64 dovecot-2.0.9-7.el6.x86_64
less了什么东西？
您的示例有两次用户名，这将使任何login尝试失效。 在testingPLAIN auth时，loginstring是一个base64编码的NULL分隔的用户名和密码，如下所示：
perl -MMIME::Base64 -e 'print encode_base64("\000user\000password");' AHVzZXIAcGFzc3dvcmQ=
另一种testing是LOGIN方法
perl -MMIME::Base64 -e 'print encode_base64("user")' dXNlcg== perl -MMIME::Base64 -e 'print encode_base64("password")' cGFzc3dvcmQ=
其中S：是服务器，C：是客户端的响应
openssl s_client -starttls smtp -connect localhost:25 C: EHLO localhost.localdomain S: 250- Hello localhost [127.0.0.1], pleased to meet you S: 250-AUTH LOGIN PLAIN C: AUTH PLAIN S: 334 C: AHVzZXIAcGFzc3dvcmQ= S: 235 2.0.0 OK Authenticated
C: AUTH LOGIN S: 334 VXNlcm5hbWU6 C: dXNlcg== S: 334 UGFzc3dvcmQ6 C: cGFzc3dvcmQ= S: 235 2.0.0 OK Authenticated