我已经阅读了这个主题的现有答案，但是我仍然无法连接。 我创build了一个AWS密钥并保存到我的〜/ .ssh文件夹中。
命令：
ssh -i ~/.ssh/jdrake.pem [email protected] -v 结果是：
OpenSSH_5.2p1, OpenSSL 0.9.8r 8 Feb 2011 debug1: Reading configuration data /etc/ssh_config debug1: Connecting to ec2-75-101-217-120.compute-1.amazonaws.com [75.101.217.120] port 22. debug1: Connection established. debug1: identity file /Users/jdrake/.ssh/jdrake.pem type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.3p1 Debian-3ubuntu7 debug1: match: OpenSSH_5.3p1 Debian-3ubuntu7 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.2 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host 'ec2-75-101-217-120.compute-1.amazonaws.com' is known and matches the RSA host key. debug1: Found key in /Users/jdrake/.ssh/known_hosts:6 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey debug1: Next authentication method: publickey debug1: Offering public key: /Users/jdrake/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/jdrake/.ssh/jdrake.pem debug1: read PEM private key done: type RSA debug1: Authentications that can continue: publickey debug1: No more authentication methods to try. Permission denied (publickey).
我也尝试了不同的用户（ubuntu，root，jdrake）而没有成功。 我在OSX上。
从上面的日志中，您将连接到一台Ubuntu机器：
debug1: Remote protocol version 2.0, remote software version OpenSSH_5.3p1 Debian-3ubuntu7
因此，该框的默认用户名是ubuntu ，而不是仅用于Amazon Linux的ec2-user 。
closures这个是因为它在3年前，我不记得最终的解决scheme。