重写请求url并传递给fast-cgi

我有一个服务器块，如下所示：

server { listen 80; # ... location / { try_files $uri $uri/ /index.php?$query_string; # I've tried adding "$uri.php" like so, but it downloads the php file instead. # try_files $uri $uri/ $uri.php /index.php?$query_string; } location ~ \.php$ { fastcgi_split_path_info ^(.+\.php)(/.+)$; fastcgi_pass unix:/var/run/php/php7.1-fpm.sock; fastcgi_index index.php; include fastcgi_params; } } 

如果这样的请求来自http://example.com/random/page ，我需要Nginx将其重写到http://example.com/random/page.php而无需更改用户的url。 它还需要将该请求传递给其他位置块。 如果该文件不存在，它应该返回一个404。我怎样才能做到这一点？

 server { listen 80; ... location / { try_files $uri $uri/ @rewrite; } location @rewrite { rewrite ^ $uri.php last; } location ~ \.php$ { try_files $uri =404; fastcgi_pass unix:/var/run/php/php7.1-fpm.sock; include fastcgi_params; } }