mysql -u root -pmysql; SELECT TABLE_NAME AS "Table Name", table_rows AS "Quant of Rows", ROUND((data_length + index_length)/1024/1024,2) AS "Total Size Mb" FROM information_schema.TABLES WHERE information_schema.TABLES.table_schema='database_name'; 我想创build一个shell脚本来执行这些命令并返回结果。
我怎样才能通过shell脚本运行这个命令？
又一个答案…
mysql -uroot -pmysql -B --skip-column-names -e'SELECT TABLE_NAME AS "Table Name", table_rows AS "Quant of Rows", ROUND((data_length + index_length)/1024/1024,2) AS "Total Size Mb" FROM information_schema.TABLES WHERE information_schema.TABLES.table_schema="database_name"'
另外，如果您要在脚本中input密码，则应该保证密码不会被不想知道密码的人读取。
mysql -u root -pmysql << eof SELECT TABLE_NAME AS "Table Name", table_rows AS "Quant of Rows", ROUND((data_length + index_length)/1024/1024,2) AS "Total Size Mb" FROM information_schema.TABLES WHERE information_schema.TABLES.table_schema='database_name'; eof
或者，相当于这样的事情：
echo 'SELECT TABLE_NAME AS "Table Name", table_rows AS "Quant of Rows", ROUND((data_length + index_length)/1024/1024,2) AS "Total Size Mb" FROM information_schema.TABLES WHERE information_schema.TABLES.table_schema="database_name";' | mysql -u root -pmysql
编辑：固定报价。